第三步：守住坏行

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（每道题开头都有同一段：被测的 clean(rows)（去空白、空数量当 0、整行去重、转不了的记行号）、静音的 run()，和造记录用的 row(store, qty)。）

补一条用例：数量是 five 的行不进 good、行号记进 bad（表头算第 1 行，它在第 2 行）。它对正确版本要过、对 clean_swallow 要挂。输出两次 run。

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← 第二步：守住去重第四步：空数量当 0 →

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代码编辑器

语言： Ctrl + Enter 运行

import io, unittest

def clean(rows):
    good, bad, seen = [], [], set()
    for i, r in enumerate(rows, 2):
        r = {k: v.strip() for k, v in r.items()}
        if r["qty"] == "":
            r["qty"] = "0"
        key = tuple(r.values())
        if key in seen:
            continue
        seen.add(key)
        try:
            r["qty"] = int(r["qty"])
        except ValueError:
            bad.append(i)
            continue
        good.append(r)
    return good, bad

def run(*cases):
    suite = unittest.TestSuite()
    for c in cases:
        suite.addTests(unittest.defaultTestLoader.loadTestsFromTestCase(c))
    r = unittest.TextTestRunner(stream=io.StringIO()).run(suite)
    return str(r.testsRun) + "/" + str(len(r.failures)) + "/" + str(len(r.errors))

def row(store, qty):
    return {"store": store, "qty": qty}

def clean_no_strip(rows):
    good, bad, seen = [], [], set()
    for i, r in enumerate(rows, 2):
        if r["qty"] == "":
            r = dict(r, qty="0")
        key = tuple(r.values())
        if key in seen:
            continue
        seen.add(key)
        try:
            r = dict(r, qty=int(r["qty"]))
        except ValueError:
            bad.append(i)
            continue
        good.append(r)
    return good, bad

def clean_no_dedupe(rows):
    good, bad = [], []
    for i, r in enumerate(rows, 2):
        r = {k: v.strip() for k, v in r.items()}
        if r["qty"] == "":
            r["qty"] = "0"
        try:
            r["qty"] = int(r["qty"])
        except ValueError:
            bad.append(i)
            continue
        good.append(r)
    return good, bad

def clean_swallow(rows):
    good, bad, seen = [], [], set()
    for i, r in enumerate(rows, 2):
        r = {k: v.strip() for k, v in r.items()}
        if r["qty"] == "":
            r["qty"] = "0"
        key = tuple(r.values())
        if key in seen:
            continue
        seen.add(key)
        try:
            r["qty"] = int(r["qty"])
        except ValueError:
            r["qty"] = 0
        good.append(r)
    return good, bad

def make(fn):
    class T(unittest.TestCase):
        def test_bad_row(self):
            # TODO: good, bad = fn([row("东门", "five")])；断言 good == [] 且 bad == [2]
            pass
    return T

print(run(make(clean)) + "|" + run(make(clean_swallow)))

本次输入：

输出：

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第三步：守住坏行

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