五项一起对得上吗

把这条路线算过的东西一次验完。运行下面这段程序：

def classify(b, o, t):
    if o == t:
        return "same"
    if o == b:
        return "theirs"
    if t == b:
        return "ours"
    return "conflict"

def kinds(base, ours, theirs):
    return [classify(b, o, t)
            for b, o, t in zip(base, ours, theirs)]

def merge3(base, ours, theirs):
    out = []
    for b, o, t in zip(base, ours, theirs):
        k = classify(b, o, t)
        if k == "conflict":
            out.append("<<<<<<< ours")
            out.append(o)
            out.append("=======")
            out.append(t)
            out.append(">>>>>>> theirs")
        elif k == "theirs":
            out.append(t)
        else:
            out.append(o)
    return out

def is_marker(line):
    return line.startswith(("<<<<<<<", "=======", ">>>>>>>"))

def resolve(merged, take):
    """take: "ours" 取上半段，"theirs" 取下半段，"both" 两段都留"""
    out = []
    i = 0
    while i < len(merged):
        if merged[i].startswith("<<<<<<<"):
            sep = merged.index("=======", i)
            end = merged.index(">>>>>>>" + " theirs", i)
            mine = merged[i + 1:sep]
            yours = merged[sep + 1:end]
            if take == "ours":
                out += mine
            elif take == "theirs":
                out += yours
            else:
                out += mine + yours
            i = end + 1
        else:
            out.append(merged[i])
            i += 1
    return out

base = ['HOST = "localhost"', 'PORT = 8000', 'DEBUG = False',
        'TIMEOUT = 30', 'RETRY = 1', 'LOG = "app.log"']
ours = ['HOST = "localhost"', 'PORT = 8080', 'DEBUG = True',
        'TIMEOUT = 60', 'RETRY = 1', 'LOG = "main.log"']
theirs = ['HOST = "0.0.0.0"', 'PORT = 9000', 'DEBUG = True',
          'TIMEOUT = 30', 'RETRY = 3', 'LOG = "sys.log"']
k = kinds(base, ours, theirs)
m = merge3(base, ours, theirs)
r = resolve(m, "theirs")
ok = (k.count("conflict") == 2
      and len(m) == 14
      and sum(1 for l in m if is_marker(l)) == 6
      and len(r) == 6
      and not any(is_marker(l) for l in r))
print(ok)