每个进程几只手

（每道题开头都有同一段：那张线程表 PSL，和把它切成字典列表的 rows()——每个字典有 pid / tid / nlwp / stat / cpu / comm 六项。）

按 PID 分组数线程，和 NLWP 对一对：

PSL = '''PID  TID  NLWP STAT  %CPU  COMM
1    1    1    Ss    0.0   bash
12   12   1    S     0.0   收数据.sh
17   17   4    Ssl   49.8  算账
17   18   4    Rsl   49.6  算账-核对
17   19   4    Ssl   0.0   算账-写盘
17   20   4    Ssl   0.1   算账-心跳
21   21   2    Ssl   0.0   通知
21   22   2    Ssl   0.0   通知-等待'''

def rows(text):
    out = []
    for line in text.split("\n")[1:]:
        pid, tid, nlwp, stat, cpu, comm = line.split()
        out.append({"pid": int(pid), "tid": int(tid), "nlwp": int(nlwp), "stat": stat, "cpu": float(cpu), "comm": comm})
    return out

r = rows(PSL)
count = {}
for x in r:
    count[x["pid"]] = count.get(x["pid"], 0) + 1
ok = all(count[x["pid"]] == x["nlwp"] for x in r)
print(",".join(str(k) + ":" + str(v) for k, v in sorted(count.items())) + "/" + str(ok))