一段代码的完整账

运行下面这段程序，填写它打印出来的结果。

STAGES = 5

def one_by_one(n):
    return n * STAGES

def pipelined(n):
    return n + STAGES - 1

n = 8
hazards = 2
stall = 2
wrong = 3
flush = 3
base = pipelined(n)
extra = hazards * stall + wrong * flush
print(str(base) + "/" + str(extra) + "/" + str(base + extra))