改成各改各的块

运行下面这段程序，填写它打印出来的结果。

BLK = 4

def traffic(seq):
    owner = {}
    moves = 0
    for core, addr in seq:
        b = addr // BLK
        if owner.get(b, -1) != core:
            moves = moves + 1
            owner[b] = core
    return moves

same_block = [(0, 0), (1, 1), (0, 0), (1, 1)]
diff_block = [(0, 0), (1, 4), (0, 0), (1, 4)]
print(str(traffic(same_block)) + "/" + str(traffic(diff_block)))