⚠️ 把数组交给函数之后

（本条路线统一用 gcc -std=c11 -O0 编译）这次把数组传进了两个函数，长度是单独传进去的：

#include <stdio.h>

#define N 5

int sum_of(const int *a, int n);
int max_of(const int *a, int n);

int main(void) {
    int a[N] = {10, 20, 30, 40, 50};
    printf("%d/%d/%d\n", N, sum_of(a, N), max_of(a, N));
    return 0;
}

int sum_of(const int *a, int n) {
    int s = 0;
    for (int i = 0; i < n; i++) s += a[i];
    return s;
}

int max_of(const int *a, int n) {
    int m = a[0];
    for (int i = 1; i < n; i++) if (a[i] > m) m = a[i];
    return m;
}