查一个从没加过的

同一个过滤器。运行下面这段程序：

def h1(k):
    return k % 8

def h2(k):
    return (k * 3) % 8

def add(bits, k):
    bits[h1(k)] = 1
    bits[h2(k)] = 1

def check(bits, k):
    if bits[h1(k)] == 1 and bits[h2(k)] == 1:
        return "可能在"
    return "肯定不在"

bits = [0] * 8
for k in [17, 24, 15]:
    add(bits, k)
print(check(bits, 10))