谁没有对应的

两个方向各找一次"没有对应的"。输出：没有供应商的商品名、没供过货的供应商名（用 / 隔开）。

goods                                 supplier
id name    cat  price stock sup_id     id name  city  parent_id
 1 绿茶    饮料     6    12      1      1 佳农  杭州       (空)
 2 红茶    饮料     6     0      1      2 康泉  杭州          1
 3 苏打水  饮料     5  (空)      2      3 文兴  苏州       (空)
 4 薯片    零食     8     7      2      4 远丰  南京          3
 5 海苔    零食    12     3   (空)
 6 巧克力  零食    15  (空)      3     tag              goods_tag
 7 铅笔    文具     2    40      3     1 热销            1-1  1-2
 8 笔记本  文具     9     5      3     2 新品            4-1  6-3
 9 橡皮    文具     3     0   (空)     3 特价            7-1  8-3
10 冰红茶  饮料     4    20      1

import sqlite3
db = sqlite3.connect(":memory:")
db.executescript("""
CREATE TABLE supplier (id INTEGER PRIMARY KEY, name TEXT NOT NULL UNIQUE,
                       city TEXT NOT NULL, parent_id INTEGER);
CREATE TABLE goods (id INTEGER PRIMARY KEY, name TEXT NOT NULL UNIQUE,
                    cat TEXT NOT NULL, price INTEGER NOT NULL,
                    stock INTEGER, sup_id INTEGER);
CREATE TABLE tag (id INTEGER PRIMARY KEY, name TEXT NOT NULL UNIQUE);
CREATE TABLE goods_tag (goods_id INTEGER, tag_id INTEGER);
""")
db.executemany("INSERT INTO supplier VALUES (?,?,?,?)", [
    (1, "佳农", "杭州", None), (2, "康泉", "杭州", 1),
    (3, "文兴", "苏州", None), (4, "远丰", "南京", 3)])
db.executemany("INSERT INTO goods VALUES (?,?,?,?,?,?)", [
    (1, "绿茶", "饮料", 6, 12, 1),   (2, "红茶", "饮料", 6, 0, 1),
    (3, "苏打水", "饮料", 5, None, 2), (4, "薯片", "零食", 8, 7, 2),
    (5, "海苔", "零食", 12, 3, None),  (6, "巧克力", "零食", 15, None, 3),
    (7, "铅笔", "文具", 2, 40, 3),   (8, "笔记本", "文具", 9, 5, 3),
    (9, "橡皮", "文具", 3, 0, None),   (10, "冰红茶", "饮料", 4, 20, 1)])
db.executemany("INSERT INTO tag VALUES (?,?)", [(1, "热销"), (2, "新品"), (3, "特价")])
db.executemany("INSERT INTO goods_tag VALUES (?,?)", [
    (1, 1), (1, 2), (4, 1), (6, 3), (7, 1), (8, 3)])
a = db.execute("SELECT g.name FROM goods g "
               "LEFT JOIN supplier s ON g.sup_id = s.id "
               "WHERE s.id IS NULL ORDER BY g.id").fetchall()
b = db.execute("SELECT s.name FROM supplier s "
               "LEFT JOIN goods g ON g.sup_id = s.id "
               "WHERE g.id IS NULL ORDER BY s.id").fetchall()
print("".join(r[0] for r in a) + "/" + "".join(r[0] for r in b))