第一个和最后一个排列
生成 1、2、3 的全部排列。运行下面这段程序:
#include <cstdlib>
#include <iostream>
#include <string>
#include <vector>
using namespace std;
void perm_dfs(const vector<int>& a, vector<int>& path, vector<bool>& used, vector<vector<int>>& res) {
if (path.size() == a.size()) {
res.push_back(path);
return;
}
for (size_t i = 0; i < a.size(); i++) {
if (used[i]) continue;
used[i] = true;
path.push_back(a[i]);
perm_dfs(a, path, used, res);
used[i] = false;
path.pop_back();
}
}
vector<vector<int>> perm(const vector<int>& a) {
vector<vector<int>> res;
vector<int> path;
vector<bool> used(a.size(), false);
perm_dfs(a, path, used, res);
return res;
}
string join(const vector<int>& v) {
string s;
for (size_t i = 0; i < v.size(); i++) s += (i ? "," : "") + to_string(v[i]);
return s;
}
int main() {
vector<vector<int>> r = perm({1, 2, 3});
cout << join(r.front()) << "/" << join(r.back()) << endl;
}
(本题用 g++ -std=c++17 -O0 编译。)
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