访问 /time 回什么

按简易 HTTP，serve_http 处理 GET /time，响应体是什么？（看 ROUTES）

socket 上的极简 HTTP：请求行形如 GET /path HTTP/1.1。parse_req(raw) 交回 (方法, 路径)；build_resp(status, body) 拼「状态行+空行+体」；serve_http(raw) 命中 ROUTES({"/","/time","/echo"}) 回 200、否则 404。

ROUTES = {"/": "hi", "/time": "now", "/echo": "echo"}


def parse_req(raw):
    # 取请求行的方法和路径：GET /path HTTP/1.1 -> ("GET", "/path")
    line = raw.split(b"\r\n", 1)[0].decode()
    method, path, _ = line.split(" ")
    return method, path


def build_resp(status, body):
    # 拼一个最小 HTTP 响应：状态行 + 空行 + 体
    reason = {200: "OK", 404: "Not Found"}.get(status, "OK")
    head = "HTTP/1.1 " + str(status) + " " + reason + "\r\n\r\n"
    return head.encode() + body.encode()


def serve_http(raw):
    # 路由：命中 ROUTES 回 200+内容，否则 404
    method, path = parse_req(raw)
    if path in ROUTES:
        return build_resp(200, ROUTES[path])
    return build_resp(404, "no")

resp = serve_http(b"GET /time HTTP/1.1\r\n\r\n")
print(resp.decode().split("\r\n\r\n", 1)[1])